USA Bus Lines

HOMEWORK HELP PLEASE! PLEASE READ!?

Hello! Im really bad in math and I just came upon. So if you know to do this please show me how. (this is 7th grade pre-algebra math) thanx-you! ^^ 1) a charter bus service charges $125 transportation fee plus $8.50 per passenger. This is represented by the function c=8.5p+125, where c is the total cost based on P passengers. What is the total cost of transportation for the following numbers of passengers: 50, 100, 150, 200, and 250? 2) A 60 yard piece of sting is divided into three pieces. The first piece is twice the length of the second piece, and the third piece is three times the length of the second piece. What is the length in yards of the longest piece? 3) During which of the following races did the fastest average speed occur? Race | Distance (m) | Time (s) --------------------------------------... 1 | 100 | 10 2 | 240 | 20 3 | 800 | 125 4 | 5000 | 800

Public Comments

1. 1. c=8.5p+125 a) 8.5(50) + 125 = c b) 8.5(100) + 125 = c c) 8.5(150) + 125 = c d) 8.5(200) + 125 = c e) 8.5(250) + 125 = c 2) p1 = 20yd, p2 = 10yd, p3 = 30yd. Third piece, 30yards. 4) Divide to find the "unit time" or average time Race 1: 100/10 = 10m/s Race 2: 240/20 = 20m/s Race 3: 800/125 = 6.4m/s Race 4: 5000/800 = 6.25m/s Race 4 had the fastest average speed. Glad to help =) Race 4
2. for the first one plug in 50,100,150,200, and 250 for p so multiply 8.5 by 50and add 125 then that's your answer and so forth
3. 1. You solve the equation 5 times using the given numbers as p 2.lets say the second piece is x 60=2x+x+3x so 60=6x so x=10 we know that the third piece is 3x long so it's 30 feet long 3. you do distance/time and you get the average speed 10, 12, 6.4 and 6.25 so the second one is the fastest
4. 1) 50-----550 100-----975 150----1400 200-----1825 250---2250 2) 30 3) fastes are race 4 then race 3
5. 1) c=8.5(50)+125 c=8.5(100)+125 c=8.5(150)+125 c=8.5(200)+125 c=8.5(250)+125 2) 2x+x+3x=60 6x=60 x=10 3) 100/10 = 10 240/20 = 12 800/125 = 6.4 5000/800 = 6.25
6. 2) I will answer this with variables. X=first piece of string Y=second piece of string Z=third piece of string The known information: X+Y+Z=60 X=2Y --> it says "twice the length of second piece", so multiply by 2 Z=3Y --> same concept as above Use substitution in the first equation. So... you can replace X and Z with the equations for them: 2Y+Y+3Y=60 --> at this stage just solve for Y, if you know how... Add common variables: 6Y=60 Divide both sides by 6 to isolate Y: Y=10 yards. Now solve for the two other variables using substitution once again: X=2Y X=2(10) X=20 yards Z=3Y Z=3(10) Z=30 yards... So the third piece of string is the longest: 30 yards. I'm glad I could help! I'm in 6th Grade and in Algebra 1. I understand if you don't trust my answer since my small age, but I'm pretty sure I did it correctly. Don't base your answers for math off of the internet though: ask your teacher or other students in your class for help.
7. 1.) 50 passengers: c=8.5(50)+125 c= 425 + 125 c = 550 100 passengers: c=8.5(100)+125 c= 850 + 125 c = 975 150 passengers: c=8.5(150)+125 c = 1275 + 125 c = 1400 200 passengers: c=8.5(200)+125 c = 1700 + 125 c = 1825 250 passengers: c=8.5(250)+125 c = 2125 + 125 c = 2250 2.) x = length of second piece 2x = length of first piece 3x = length of third piece total length = x + 2x + 3x = 60 yards 6x = 60 yards x = 10 yards first piece is 20 yards long second piece is 10 yards long third and longest piece is 30 yards long 3.) speed = distance / time Race | Distance (m) | Time (s) | Average Speed (m/s) --------------------------------------------------------------------- 1------------ | 100 | ----------- 10 | ----------- 10 2------------ | 240 | ------------ 20 | ----------- 12 3------------ | 800 | ----------- 125 | --------- 6.4 4------------ | 5000 | ----------- 800 | --------- 6.25 fastest average speed: race 2